CHAPTER 3 : Logic Design





Chapter 3 : Logic Design
Sum of Product(SOP) and Product of Sum(POS)

Basically,
E = ((A&B) + (A&C) + (B+C)) & (A&B&C)’
       (A&B) & (A&B&C)’
   = (A&B&C’)
       (A&C) & (A&B&C)’
   = (A&C&B’)
       (B&C) & (A&B&C)’
   = (B&C&A’)

Then just sum up all the products...

E = (A&B&C’) + (A&C&B’) + (B&C&A’)
To get the product of sum.


On the contrary,
                  for S.O.P,


Is required to use DeMorgan's theorem. We do not have the sufficient know-how of this theorem. If you want to learn more, click here. 

by:
nur fariny sabtu

1 comments:

Unknown said...

yeay!!! i've better understanding in this topic now.. TQVM marafasha.. <3

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