Chapter 3 :
Logic Design
Sum of Product(SOP) and Product of
Sum(POS)
Basically,
E = ((A&B)
+ (A&C) + (B+C)) & (A&B&C)’
(A&B)
& (A&B&C)’
= (A&B&C’)
(A&C)
& (A&B&C)’
= (A&C&B’)
(B&C) &
(A&B&C)’
= (B&C&A’)
Then just sum up all the products...
E = (A&B&C’) + (A&C&B’) + (B&C&A’)
To get the product of
sum.
On the contrary,
for S.O.P,
Is required to use DeMorgan's theorem. We do not have the sufficient know-how of this theorem. If you want to learn more, click here.
by:
nur fariny sabtu